3x^2-(2x^2-12)+(-20)=

Solution for 3x^2-(2x^2-12)+(-20)= equation:

Simplifying
3x2 + -1(2x2 + -12) + (-20) = 0

Reorder the terms:
3x2 + -1(-12 + 2x2) + (-20) = 0
3x2 + (-12 * -1 + 2x2 * -1) + (-20) = 0
3x2 + (12 + -2x2) + (-20) = 0
3x2 + 12 + -2x2 + -20 = 0

Reorder the terms:
12 + -20 + 3x2 + -2x2 = 0

Combine like terms: 12 + -20 = -8
-8 + 3x2 + -2x2 = 0

Combine like terms: 3x2 + -2x2 = 1x2
-8 + 1x2 = 0

Solving
-8 + 1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1x2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1x2 = 0 + 8
1x2 = 0 + 8

Combine like terms: 0 + 8 = 8
1x2 = 8

Divide each side by '1'.
x2 = 8

Simplifying
x2 = 8

Take the square root of each side:
x = {-2.828427125, 2.828427125}